思路:我特喵的直接暴力解法
/**
* @param {number[]} nums
* @return {number[]}
*/
var sortArrayByParityII = function(nums) {
let arr = []
let arr_ou = []
let arr_ji = []
nums.forEach(data => {
data % 2 === 0 ? arr_ou.push(data) : arr_ji.push(data)
})
for (let i = 0; i<arr_ji.length ;i++) {
arr[i * 2] = arr_ou[i]
arr[i * 2 + 1] = arr_ji[i]
}
return arr
};
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